lnx-6[ln(x-2)+ln(x+2)]=x

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Solution for lnx-6[ln(x-2)+ln(x+2)]=x equation: 


Simplifying
lnx + -6[ln(x + -2) + ln(x + 2)] = x

Reorder the terms:
lnx + -6[ln(-2 + x) + ln(x + 2)] = x
lnx + -6[(-2 * ln + x * ln) + ln(x + 2)] = x
lnx + -6[(-2ln + lnx) + ln(x + 2)] = x

Reorder the terms:
lnx + -6[-2ln + lnx + ln(2 + x)] = x
lnx + -6[-2ln + lnx + (2 * ln + x * ln)] = x
lnx + -6[-2ln + lnx + (2ln + lnx)] = x

Reorder the terms:
lnx + -6[-2ln + 2ln + lnx + lnx] = x

Combine like terms: -2ln + 2ln = 0
lnx + -6[0 + lnx + lnx] = x
lnx + -6[lnx + lnx] = x

Combine like terms: lnx + lnx = 2lnx
lnx + -6[2lnx] = x

Remove brackets around [2lnx]
lnx + -6 * 2lnx = x

Multiply -6 * 2
lnx + -12lnx = x

Combine like terms: lnx + -12lnx = -11lnx
-11lnx = x

Solving
-11lnx = x

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '-11nx'.
l = -0.09090909091n-1

Simplifying
l = -0.09090909091n-1

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